What reaction occurs when bromine is added to an aqueous solution of iodide ions?
this is the same as your last one, find the half-reaction with the largest potential, and that's the direction that the reaction will run in
How do I find the largest potential for this one?
I don't have the amount of volts like the last one...
then we get to assume that the reaction will happen anyway
this is a single-displacement reaction, do you know your classes of reaction?
what do you mean be classes?
reactions tend to fit into one of 5 general patterns, we call classes. The reaction that's happening here is: \(Br_2 + I^{-1}(aq) \rightarrow \)
both bromine and iodine are halogens, so both will form the same kind of ion (-1). Both are also \(diatomic\) molecules when they are neutral
okay.... I'm still confused. sorry.
the bromine will \(replace\) the iodide ions, and the iodide will become io\(dine\), and will be oxidized
So will the product be \(I_2+2Br^-\)?
and then to balance it, you put a 2 in front of the I in the reactant?
or is my product wrong?
that's exactly right, your overall reaction will be \(Br_2 + 2I^{-1} \rightarrow I_2 +2Br^{-1}\)
see how when one reactant gets oxidized, the other one must get reduced? If one reactant gives up an electron, the other one must take it
okay. thanks :) I really appreciate your help. and yes I do.
YW
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