What is the slope of a line perpendicular to x - 3y = 9?
@dan815 @shrutipande9
Convert to slope-intercept form first.
x - 3y = 9 Subtract 'x' to both sides: -3y = -x + 9 Divide -3 to both sides: y = 1/3x - 3
get your equation into the standard form y=mx+c then your perpendicular gradient to this line would be the negative reciprocal of m
Now it's in slope intercept form, y = mx + b, where 'm' is the slope, and 'b' is the y-intercept.
So what's the slope here?
idk how to do that stuff
What's the slope of y = 1/3x - 3? y = mx + b, 'm' is the slope
so the answer is 1?
Not quite, it's the fraction before 'x'
so its 3?
Fraction. \(\sf y = \dfrac{1}{3}x - 3\)
The slope is \(\sf\dfrac{1}{3}\).
Perpendicular lines have opposite reciprocal slopes, so switch the two numbers, can you do that?
this is confusing!
Not really. \(\sf y = \color{red}mx + b\) \(\sf y = \color{red}{\dfrac{1}{3}}x-3\) The red parts are the slope.
no the answer is 1/3?
so*
No, that's the slope of this line, it's asking for the slope that's perpendicular to the line.
so -3?
Yes!
thats bullcrap lol
That's our answer. \(\sf\dfrac{1}{3}\) Flip the fraction: \(\sf\dfrac{3}{1} \rightarrow 3\) Multiply by -1: \(\sf 3 \times -1 = -3\)
Lol, you'll get used to it :P
thanks
i got like 5 more lol
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