Kevin’s family has a history of diabetes. The probability that Kevin would inherit this disease is 0.75. Kevin decides to take a test to check if he has the disease. The accuracy of this test is 0.85. We now know that the test predicted that Kevin does not have the disease. Using this information, calculate the probability that Kevin does not have diabetes after the test was taken. 0.0925 0.3565 0.4827 0.6538 0.8765
@YanaSidlinskiy
if A and B are two independent events, then P(A∩B) = P(A)xP(B) The probability that Kevin inherits the disease and the accuracy of the test are independent, so the intersection of the two probabilities = **** ?
let A=kevin has the disease let B=the test is positive for the disease We want the probability of A given B, or\[P(A|B)=\frac{P(A\cap B)}{P(B)}\]
Are we going to be drawing a tree? :)
the events are not independent - having a positive test changes the likelihood of having the disease and vice versa
yes, tree is a good idea
May you draw it :)
let's draw it together the first fork should be between having the disease and not having the disease. What does that look like?
.85 and .15
that is the probability of the test being accurate what is the probability of having the disease? what is the probability of not having the disease?
probability of him having it is .75 not having it is .25
right, so we get a figure like so|dw:1428939452193:dw|now, if he has the disease (A), what is the probability that the test is positive (B) ?
Oh, I thought they were independent.
.15?
To decide if two events are independent, just think about whether or not knowing one piece of information influences your belief about the other. Doesn't knowing the test is positive influence your belief about whether or not he has the disease?
@cole1117 so you claim that if I have the disease, the test will only correctly tell me that I have the disease 15% of the time? Why?
85% accuracy means that if you have the disease, the test should be positive 85% of the time, and if you don't have it, the test should be negative 85% of the time.
I don not know. I thought that was what the question stated he only had a 15% chance of the test being incorrect.
85% accuracy means that if you have the disease, the test should be positive 85% of the time, and if you don't have it, the test should be negative 85% of the time. If he has the disease (A) what is the probability that the test is positive (B)?
85
right, and what is the probability that the test is negative?
15
Yes, so that will look like so|dw:1428940256131:dw|
i had mislabeled the bottom branch before, oops
It is fine. Now what?
|dw:1428940315882:dw|
what is the probability of the test being positive when he doesn't have the disease?
85
no no 15
right, good save|dw:1428940391497:dw|
Yea I wasn't thinking at first.
ok, so now to our formula we know the test is positive, and given that we want the probability of him having the disease this is\[P(A|B)=\frac{P(A\cap B)}{P(B)}\]how are we still?
what does |dw:1428940541647:dw| mean?
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