What is the magnitude of B?
speed=2.64*10^7
radius .160m
R=mv/|q|B

Question

What is the magnitude of B?
speed=2.64*10^7
radius .160m
R=mv/|q|B

anonymous · Answer

Can you describe what |q| and B are in the equation you showed?

anonymous · Answer

|q| is the magnitude of the charge and B is the magnitude of the magnetic field

anonymous · Answer

i know its just plugging in the known values but I do not know how to find |q|

anonymous · Answer

Do you know how many elementary charges are involved? If you, multiply that by the value of the elementary charge.

anonymous · Answer

An electron inside of a television tube moves with a speed of 2.64×107m/s . It encounters a region with a uniform magnetic field oriented perpendicular to its trajectory. The electron begins to move along a circular arc of radius 0.160m . What is the magnitude of the magnetic field?

anonymous · Answer

Since you have only one electron, just use e, the elementary charge.

anonymous · Answer

okay which would be 1.60*10^-19

anonymous · Answer

so B=mv/qr?

anonymous · Answer

$$=(1.60*10^-19)(2.64*10^7)/(9.10*10^-31)(.160)$$

anonymous · Answer

?

anonymous · Answer

Yes, go ahead with that. (The equation editor doesn't seem to be working properly today.)