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Mathematics 11 Online
OpenStudy (thedj4jc):

Simplify!

OpenStudy (thedj4jc):

\[\sqrt{2x}(7+\sqrt{2x})\]

OpenStudy (thedj4jc):

A. \[2x+7*\sqrt{2x}\] B. \[2x+7*\sqrt{2}\] C. \[2+7\sqrt{2x}\]

OpenStudy (studygurl14):

First step is to distribute the \(\sqrt{2x}\) to the \(7\) and \(\sqrt{2x}\)

OpenStudy (thedj4jc):

What do you mean?

OpenStudy (studygurl14):

\(\Large \sqrt{2x}(7+\sqrt{2x})\rightarrow \sqrt{2x}(7) + \sqrt{2x}(\sqrt{2x})\rightarrow?\)

OpenStudy (thedj4jc):

\[14\sqrt{x} + 2\sqrt{x}\]??

OpenStudy (studygurl14):

Not quite. When you multiply a radical by a regular number, the number goes on the outside. When you multiply two radicals, you multiply the numbers under the radical. \(\Large \sqrt{2x}(7)\rightarrow 7\sqrt{2x}\) \(\Large (\sqrt{2x})(\sqrt{2x})\rightarrow \sqrt{(2x)(2x)}\) When you have something being multiplied against itself under a squart root, you can simplify it like this:\(\Large \sqrt{(2x)(2x)}\rightarrow 2x\)

OpenStudy (thedj4jc):

Oh, that makes sense.

OpenStudy (studygurl14):

:)

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