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Mathematics 9 Online
OpenStudy (anonymous):

Can someone check my answers please? Use the functions to answer the question. f(x) = |x| + 1 Find the range. all real numbers greater than or equal to 0 [My answer] all real numbers greater than 0 all real numbers greater than or equal to 1 all real numbers greater than 1 f(x)=2/x, g(x)=|x|-1 What is the domain? {x| x e real numbers} {my answer} {x|x does NOT = 0} {x|x does NOT=0 or x does NOT = 1} {x|x does NOT = -1 or x does NOT equal 1}

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@jim_thompson5910 @aaronq

OpenStudy (anonymous):

for your 1st question, the correct answer is: all real numbers greater than or equal to 1

OpenStudy (anonymous):

@plusky How do you know?

OpenStudy (anonymous):

@inowalst @Nnesha

OpenStudy (anonymous):

@welshfella

OpenStudy (anonymous):

@paki

OpenStudy (anonymous):

@Hoslos

OpenStudy (anonymous):

Thanks for the help you guys. Really appreciate it.

OpenStudy (amistre64):

f(x) = |x| + 1 the range is determined an many ways depending on your level ofmathical prowess. let say y = |x| + 1 , the domain is all real numbers since there is no real number that causes an issue here. write the domain and transform it into the range -inf < x < inf ; now construct x into f(x), lets ||bar it all |-inf| < |x| < |inf| , for no good reason at the moment other than common sense, this is equal to saying 0 <= |x| < inf , the outcomes are between 0 and inf now add 1 to it all 1 <= |x|+1 < inf+1 , inf+1 = inf by default 1 <= f(x) < inf this is one approach

OpenStudy (anonymous):

thanks @amistre64 for the help. that's a comprehensive explanation.

OpenStudy (anonymous):

thanks @amistre64 for the help. that's a comprehensive explanation.

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