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can someone help me understand why this is equal to e^2...Limit as n-> infinity of [1+(2/n)]^n
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HI!!
what is your definition of \(e^x\)?
one is \[\lim_{n\to \infty}\left(1+\frac{x}{n}\right)^n\]
in which case replacing \(x\) by \(2\) gives \(e^2\) right of the bat
elsewise you have to take the log and use l'hopitals rule for the resulting limit you will get 2 so final answer will be \(e^2\)
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start with the original identity (from Bernoulli compounding formula, the origin of e).... \[\lim_{n \rightarrow \infty} ( 1 + \frac{1}{n})^n = e\] then play with some substitution, eg let k = 2*n or n/2 and do the limit for k -> infinity
Thank you!
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