Find the angle between the given vectors to the nearest tenth of a degree. (2 points) u = <2, -4>, v = <3, -8> 3.0° 6.0° -7.0° 16.0°
i got -7.0 not sure lol if i got it correct
how do you test if it is correct?
not sure how! actually
what approach did you take?
if using vectors, id use the dot product identity
the last thing i got was (19sqrt365)/ 365 but the decimal form doesnt match my answer
you want to take a cosine inverse if you did the rest right
|u| |v| cos(a) = u.v cos(a) = u.v/(|u| |v|) a = inverseCos(u.v/(|u| |v|)) which will either give radians or degrees depending on your calculator setting
a·b = ax·bx + ay·by = 2 · 3 + (-4) · (-8) = 6 + 32 = 38
You can find the angle between two vectors (also used to find the angle between two lines in an intersecting point) with the equation: \[Cos \alpha =\frac{ x_u x_ v + y_u y_v }{ \sqrt{x_u ^2 + y_u ^2 }\sqrt{x_v ^2 + y_v ^2} }\] of if you prefer: \[Cos \alpha = \frac{ U.V }{ \left| \left| U \right| \right|\left| \left| V \right| \right| }\]
idk why its so far apart but i used the dot approach
well, define your lengths and your dot product lets start there and correct if needed
okay so im confused on the set up then
@Owlcoffee /cdot makes a nice latex dot \(u\cdot v\)
I'll have that in mind, thanks Amistre.
u = <2, -4> sqrt(4+16) v = <3, -8> sqrt(9+64) u = <2, -4> v = <3, -8> 6+32 these are our parts right?
yes
then a = cos^(-1)(38/(sqrt(20*73)))
if your calcultor is in radian mode, then it doesn give degrees
ohh okay let me calculate this
a=cos^-1 (19/sqrt365)?
no need to simplify anything, the calculator is capable of working with the stated values
if your inputting them is awkward, then calculate 20*73 = k take the sqrt of it, write it down if need be or stick it in the calcs memory 38 / k = m now take the inverse cos of m what type of calcuator you using?
online calculator!
online, then just do this http://www.wolframalpha.com/input/?i=cos%5E%28-1%29%2838%2F%28sqrt%2820*73%29%29%29
idk if im inputting the correct thing
ohh so it would be 6.009!
yes, or in this case 6.0 seems rnded
oh i see!! I was forgetting about the radians conversion
thank you :)!!!!!!!
your welcome
would you mind helping me with another! @amistre64
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