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Identify the surface by converting to rectangular form the from the following equation \[\rho=2\cos(\phi)\]
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I'm not in calc3 but i just want to make sure i gave a friend th right answer we know that \[x^2+y^2+z^2=\rho^2=2z\]
it follows that \[x^2+y^2+(z-1)^2=1\] so the surface is a sphere with radius 1 and center (0,0,1)
@amistre64
so, it's been a while, but I'm not seeing where you got the 2z from. Shouldn't it just be 4?
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