Question

solve the logarithmic equation log7 x +log 7 (x-48)=2

Answer 1

\[\huge\rm log_7 x + \log_7 (x -48) =2 \]
what rule of log you should apply first ??
if there is positive sign how would you condense that ??

Answer 2

I know first step combine logs because they are the same and log7(x(x^2-48))=2

Answer 3

gO_Od!!!

Answer 4

log7(x^2-48X)=2

Answer 5

when you multiply variables you should add their exponents \[\huge\rm x^m \times x^n = x^{m+n}\]

Answer 6

here is where I need help I know you have to bring over the 2 but I forget what about log 7

Answer 7

\(\color{blue}{\text{Originally Posted by}}\) @sam87211
log7(x^2-48X)=2
\(\color{blue}{\text{End of Quote}}\)
this one distribute both term by x
so......

Answer 8

nvm i thought there is (x^2 -48)

Answer 9

now you have to change log form to exponential