Question

How many moles of oxygen will occupy a volume of 2.5 liters at 1.2atm and 25 degrees C?

Answer 1

PV=nRt [r=0.0821]

derive a formula..
pv/RT=nRt/Rt
n= pv/Rt

p=1.2 atm
v= 2.5 L
t= 25 deg. C convert to Kelvin +273 = 298 K
R= 0.0821 <constant

n=(1.2)(2.5) / (0.0821)(298)
n= 0.1226....... mol
n= 0.12 mol [ accd. to significant figures]

Does this help? ^v^

Answer 2

thank you!!!!!!