HELP! dilution factor!

Question

anonymous · Answer

|dw:1428979710202:dw|

anonymous · Answer

|dw:1428979825830:dw|

dtan5457 · Answer

dilution factor=dilution final/dilution initial(what you added)

anonymous · Answer

can i confirm my answer? the first one is 1251, the 2nd is 417.67?

dtan5457 · Answer

The first one is correct, but I'm getting a different answer for the 2nd one

anonymous · Answer

how come?

dtan5457 · Answer

what did you get for total volume? (dilution final)?

anonymous · Answer

total volume is 25 mL + 60 micro-litre right? since 20+40 but im not sure actually

dtan5457 · Answer

actually, i'm not sure for your 2nd question, if you add the dilutions together as dilution initial or just use the 40 micro-litre ..

dtan5457 · Answer

if you do indeed add them, you would be right.

dtan5457 · Answer

@Hoslos 
Mind clearing this up for us?

dtan5457 · Answer

@Miracrown

anonymous · Answer

According to my calculation, given that in the numerator you plot the total volume and in the denominator the amount added, then it becomes:$$\frac{ (40*10^{-6})+0.025+(20*10^{-6}) }{ 60*10^-6 }=417.67$$.

dtan5457 · Answer

oh alright, wasn't sure if you add the previous dilution to the diluted initial or not