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Mathematics 9 Online
OpenStudy (kj4uts):

Suppose that many large samples are taken from a population whose data values have a standard deviation of 112.34. Which of the following could be the standard deviation of sample means?

OpenStudy (kj4uts):

OpenStudy (kropot72):

Consider the following: The Standard Deviation of the sample means is given by \[\large \frac{\sigma}{\sqrt{n}}\] where sigma is the Standard Deviation of the population and n is the sample size. Can you now see the correct choice of answer?

OpenStudy (kropot72):

Yes, that is the Standard Deviation of the population. But keep in mind that the question is asking which of the choices is a POSSIBLE value for the standard deviation of sample means. The value of n is not given, but we know that the value of n is much greater than one. Therefore three of the answer choices cannot be correct.

OpenStudy (kropot72):

If the standard deviation of sample means was 7.48, we would have: \[\large \frac{112.34}{\sqrt{n}}=7.48\] and the sample size n is given by: \[\large n=(\frac{112.34}{7.48})^{2}=226\] If you calculated the values of n using the other choices of answer, the values would all be lees than one.

OpenStudy (kropot72):

less than one*

OpenStudy (kj4uts):

Yes, I tried them and got less than one.

OpenStudy (kj4uts):

so does that mean that 7.48 is the answer?

OpenStudy (kropot72):

That is correct. The question states "many large samples are taken", therefore the only correct choice of answer must be a value of standard deviation of sample means which results in a value of n that is much greater than one.

OpenStudy (kj4uts):

Thank you very much for your help and time :)

OpenStudy (kropot72):

You're welcome :)

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