Suppose that many large samples are taken from a population whose data values have a standard deviation of 112.34. Which of the following could be the standard deviation of sample means?
Consider the following: The Standard Deviation of the sample means is given by \[\large \frac{\sigma}{\sqrt{n}}\] where sigma is the Standard Deviation of the population and n is the sample size. Can you now see the correct choice of answer?
Yes, that is the Standard Deviation of the population. But keep in mind that the question is asking which of the choices is a POSSIBLE value for the standard deviation of sample means. The value of n is not given, but we know that the value of n is much greater than one. Therefore three of the answer choices cannot be correct.
If the standard deviation of sample means was 7.48, we would have: \[\large \frac{112.34}{\sqrt{n}}=7.48\] and the sample size n is given by: \[\large n=(\frac{112.34}{7.48})^{2}=226\] If you calculated the values of n using the other choices of answer, the values would all be lees than one.
less than one*
Yes, I tried them and got less than one.
so does that mean that 7.48 is the answer?
That is correct. The question states "many large samples are taken", therefore the only correct choice of answer must be a value of standard deviation of sample means which results in a value of n that is much greater than one.
Thank you very much for your help and time :)
You're welcome :)
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