Question

Find the point on the line y=92 x closest to the point (1,0).

Answer 1

A point on the line y = 92 x is of the form (t,92t). You need to minimise \(\sqrt{(t -1)^2 + (92t - 0)^2}\)

Answer 2

Ok, I've gotten that far. Then do I take the derivative of it and set it equal to zero?

Answer 3

I think you need to understand why you're doing the things you're doing when solving a problem

Answer 4

If it's a calculus class, yes, you can do that.

Answer 5

:) parth is such a smart person :)

Answer 6

Yes, it's because we need to find the optimal minimums, and that will eventually give us the closest values to the point. Right?

Answer 7

distance of any point on the line (t, 92t) from the point (1, 0) is given by the expression \(d(t) = \sqrt{(t-1)^2 + (92t)^2}\).

you have to minimise \(d(t)\).