Question

(3n-6)n
------- =
-2(n-2)

A. -n
B. -3n/4
C. -n/2
D. -3n/2

Answer 1

The answer is D however idk how to get that

Answer 2

\[\frac{ (3n-6)n }{ -2(n-2) }=\frac{ 3n^2-6n }{ -2(n-2) }\]

Answer 3

How???

Answer 4

\[=\frac{ 3n(n-2) }{ -2(n-2) }\]

Answer 5

what u get when u multiply 3n-6 with n?

Answer 6

3n squared

Answer 7

and 6n

Answer 8

yep

Answer 9

YAY

Answer 10

\[=\frac{ 3n^2-6n }{ -2(n-2) }\] now factorise 3n for the numerator only

Answer 11

you will get \[=\frac{ 3n(n-2) }{ -2(n-2) }\]

Answer 12

and you did that how again

Answer 13

facotrise 3n for the numerator only

Answer 14

factorise*

Answer 15

ik but how what did you use to do that

Answer 16

Sorry I get really confused on these type of questions

Answer 17

Thinking, of how to explain it to me?

Answer 18

Well, sometime we used GCF to see what's GCF in terms inside of parenthesis, then factor that out.

\(\text{GCF}(3n^2,6n) = 3n\)\

so factor \(3n\) out.

Answer 19

I don't think I've learn GCF which is making me wonder why are they giving me this to study for my end of year test, oh dear

Answer 20

so basically I don't know how to use GCF so can someone explain that to me