The coordinate plane below represents a city. Points A through F are schools in the city. Part A: Using the graph above, create a system of inequalities that only contain points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A.
Part C: William can only attend a school in his designated zone. William's zone is defined by y < -x - 1. Explain how you can identify the schools that William is allowed to attend.
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Sorry, idk :/
Thats okay
@dan815 @ckellar2 @maddiegirl @Chiko_1278
Do you know the actual coordinates?
I have the graph, i can write out the coordinates if you want?
@HackberryAbby18
where are the overlapping shaded regions?
I think i'm supposed to find that out.
Yes what are the coordinates
A (2,-3) B (-3,-4) C (-4,2) D (2,4) E (3,1) F (-2,3) @HackberryAbby18
And which ones do u need most?
A and E
@HackberryAbby18
hint: we can consider the subsequent lines: y=x and: y=-3x
What about points A and E? i don't understand how that has to do with it :c
@Michele_Laino
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Please help
part C in the picture is -4 , -2
For part C i need to explain how to find the answer. I really need help with part A right now though first :c
@HackberryAbby18
Somebody please help, iv been stuck on this for over an hour :c
@Tarantulagirl98
@dan815 @perl @nincompoop @Ashleyisakitty @Michele_Laino @HackberryAbby18
Still need help? Whole question?
omg yes thank you, please.
Part A: Using the graph above, create a system of inequalities that only contain points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A. Lets take Part A first :D
okay c:
Part A: Using the graph above, create a system of inequalities that only contain points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. Any ideas?
Only that i need to find the coords for A and E, witch are A (2,-3) E (3,1)
idk past that
here, the shaded region is given by those points whose y-coordinate satisfy the subsequent condition: \[\Large - 3x \leqslant y \leqslant x\]
Oh my @Michele_Laino ... I woulda just have done: y < 2x - 1
I believe @Michele_Laino has this atm :D After all they might do the work and explain it better than a random 10th grader xD
y < 2x - 1 instead of -3x<y <x?
when x> 0 or x=0
okay @undeadknight26 ill tag you again if i need you if thats okay? thanks for the help
Any time @AlexandervonHumboldt2 Btw welcome to Openstudy!
@Michele_Laino so does that take care of part A?
Well...I miss-tagged... Thats quite embarrassing ._.
haha cx thats okay, and thank you c:
@Michele_Laino I have this for part A, does this look right to you? A: (2,-3) E: (3,1) the shaded region is given by those points whose y-coordinate satisfy the subsequent condition -3x<y <x Shade A and E within the lines y = x and y = -3x
yes! I think that your answer is right! @AllyBearxx
Great! thank you so much ^.^ could you help me with Part B now?
Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A.
ok!
Awesome ^.^ thanks
we have to replace the coordinate of point A, into our inequality: \[ - 3x \leqslant y \leqslant x\]
for example, for point A, we have: \[\Large \begin{gathered} - 3 \times 2 \leqslant - 3 \leqslant 2 \hfill \\ - 6 \leqslant - 3 \leqslant 2 \hfill \\ \end{gathered} \] which inequality is true
I dont understand, how do i replace the coordinate of point A?
you have to rplace x with 2, and y with 3, into this inequality: \[ - 3x \leqslant y \leqslant x\]
replace*
so -3x <3 <2?
oh wait or -3x <-3 <2?
no, it is: -3*2 < -3 < 2
okay
and then what?
you have to do the same with point E
point E=(3,1)
okay so it would be 1*-3 <1 <-3?
it is: -3*1< 1 < 3
oh okay
please wait:
it is: -3*3 < 1 < 3
How did you get that?
since I have replaced x wiyh 3, and y with 1 into the subsequent inequality: \[ - 3x \leqslant y \leqslant x\]
oops..with*
oh alright, so does that take care of part B?
This is what i have for part B: You have to replace the coordinate of point A, into the inequality -3x<y <x to get -3*2 < -3 < 2, and then replace the coordinate of point E to get -3*1< 1 < 3
yes! we have solved part B
that's right!
awesome :D okay so would you help me with part C as well please?
ok!
thank you so much! c:
Part C: William can only attend a school in his designated zone. William's zone is defined by y < -x - 1. Explain how you can identify the schools that William is allowed to attend.
we have to draw the line whose equation is: y=-x-1
okay so where would that be?
here is the drawing:
it passes through point A
yes!
So would he have to go to school A?
nevertheless the question asks to us, what are the points whose y-coordinate is less than -x-1
namely the points points that lie below the straight line y=-x-1
So thats point A?
no, since A belongs to the line y=-x-1
But William would have to go to school A since his zone "line" meets A?
or is his zone below Point A? and the school hed go to would be Point B or C
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