Question

Find the rectangular coordinates of the point with the polar coordinates (3, (3/2) pi).

(0, 3)
(0, -3)
(-3, 0)
(3, 0)

Answer 1

Draw a triangle with length R=3 and angle theta=3/2*pi.

Remember:

x=rcos(theta)
y=rsin(theta)

Answer 2

Make sure your calculator is in radians.

Answer 3

i dont have a calculator :x

Answer 4

@shifuyanli @CREEPYMLPMASTER

Answer 5

sorry not good with math :/

Answer 6

\(\large {
\begin{array}{cccllll}
( 3&,&\frac{3\pi }{2})\\
r&&\theta
\end{array}\qquad
\begin{cases}
{\color{brown}{ x}}=rcos(\theta)\\
{\color{blue}{ y}}=rsin(\theta)
\end{cases}\qquad ({\color{brown}{ \square ?}},{\color{blue}{ \square ? }})
}\)

Answer 7

x=3 y=idk ??

Answer 8

well. why not use the identities
should be pretty straighforward enough
as chaise said
make sure your calculator is in Radians mode

Answer 9

notice what "r" is
notice what the angle is

notice what "x" equals
and notice what "y" equals

Answer 10

im sorry.. i really have no clue

Answer 11

well
have you covered polar coordinates yet?

Answer 12

ehh somewhat..

Answer 13

well... you may want to cover that material first then
or brush up a little more

Answer 14

okay

Answer 15

The conversion from polar to rectangular is:

\[(r, \theta)=(rcos(\theta),rsin(\theta))\]