Question

Simplify:
(3y)^4 times y^-2

Answer 1

\[\huge\rm x^{-m} = \frac{ 1 }{ x^m }\]

Answer 2

i'm still kinda confused, could you walk me through the steps?

Answer 3

sure i was afk
okay so whenever you have NEGATIVE exponent you should change that to its reciprocal
for example \[\huge\rm x^{-m} = \frac{ 1 }{ x^m }\]

Answer 4

ohhh i see so y^-2 would be 1/y-2?

Answer 5

or 1/y^2?

Answer 6

nope ......look at the exponent rules
why do you have to flip that
bec to change the negative sign to positive

Answer 7

yes that's right

Answer 8

ok

Answer 9

now (3y)^4 solve this \[\huge\rm (3y)^4 \times \frac{ 1 }{ y^2 }\]
what is (3y)^4= ?

Answer 10

um 81y times 1/y^2

Answer 11

81 and what ??

Answer 12

im not sure maybe 81y^2?

Answer 13

not sure ?? >.^
look at the previous post we just did one question same like this

Answer 14

1/81y^2?

Answer 15

nope just the parentheses part
(3y)^4 = ?

Answer 16

81y?

Answer 17

how did you get 81
? explain

Answer 18

yes bec there is 4th power of 3
what about y
y is also in parentheses .....

Answer 19

i dont know what to do with the y

Answer 20

how did we solve last question
exponent rule
(x^m)^n = x^{ m times n}

Answer 21

y there is an exponent of y which is one \[(y^1)^4\]

Answer 22

oh so 81y^1? or would i add the exponents getting 3y^5

Answer 23

\[\huge\rm (x^m)^n = x^{m \times n }\]
multiply inside exponent of variable by outside one