write the equation of the line that is perpendicular to the line y=-3x+4 that goes through the point (6,10).
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OpenStudy (jdoe0001):
hmmm what's the slope of say " y=-3x+4 " ?
OpenStudy (jdoe0001):
? so... the slope of that one is..... *rolling drums* ?
OpenStudy (jdoe0001):
heheh
OpenStudy (jdoe0001):
you may want to recheck your book on the slope-intercept form
and brush up a bit on it I'd think
OpenStudy (anonymous):
@Hero
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OpenStudy (anonymous):
@Hero
OpenStudy (anonymous):
I got y=-1/3x+12
OpenStudy (michele_laino):
two lines are perpendicular each other, when the subsequent relationship, holds:
\[\large m \times m' = - 1\]
where m and m' are the slopes of those lines
OpenStudy (michele_laino):
what is the slope of the perpendicular line?
OpenStudy (anonymous):
y=-1/3x+12
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OpenStudy (anonymous):
final answer
OpenStudy (anonymous):
"write the equation of the line that is perpendicular to the line y=-3x+4 that goes through the point (6,10)."
OpenStudy (michele_laino):
I can not give the answer directly, since the Code of Conduct
OpenStudy (anonymous):
ok
OpenStudy (michele_laino):
hint:
\[\Large \left( { - 3} \right) \times m' = - 1\]
what is m'=...?
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OpenStudy (anonymous):
it is 1/3
OpenStudy (anonymous):
sorry
OpenStudy (michele_laino):
ok!
OpenStudy (michele_laino):
no worries :)
OpenStudy (michele_laino):
now, the requested equation, is:
\[\Large y - 10 = \frac{1}{3}\left( {x - 6} \right)\]
please simplify that equation
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