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Mathematics 9 Online
OpenStudy (anonymous):

I have a series question. See below

OpenStudy (anonymous):

I am supposed to prove that xe^x converges to \[\sum_{n=0}^{\infty}\frac{ x ^{n+1} }{ n! }\]

OpenStudy (anonymous):

I found the error formula, but I am not sure how to pick the value for c. No interval was provided, and I know it is a Maclaurin. I saw online that people used 0 (the center) as c, but I am not sure why

OpenStudy (anonymous):

I hate error problems so much

OpenStudy (anonymous):

Btw I have to use the Lagrange error test. This is right before all of the other tests, so I am not supposed to use them

geerky42 (geerky42):

@zepdrix @SolomonZelman

OpenStudy (anonymous):

@TheSmartOne

OpenStudy (anonymous):

@Nnesha

OpenStudy (anonymous):

@Michele_Laino

geerky42 (geerky42):

@FibonacciChick666

OpenStudy (michele_laino):

I'm sorry, it is very late for me, since it is 2:30 a.m. (Italy time zone) and I have to go to sleep.

OpenStudy (anonymous):

Alright. Thanks anyways

OpenStudy (michele_laino):

thanks!

OpenStudy (anonymous):

I accidentally closed it

OpenStudy (anonymous):

Can you still help me?

OpenStudy (loser66):

Above my head !!

OpenStudy (anonymous):

Ok. Thanks anyways

OpenStudy (anonymous):

If you know anyone that can, please direct them here

OpenStudy (fibonaccichick666):

uhm, so personally, would take that you proved the series for e^x then it's just multiplication of taylor series I think

OpenStudy (fibonaccichick666):

for the proof bit. as for the error, I'll need to look some stuff up first

OpenStudy (fibonaccichick666):

http://www.mathopenref.com/calclagrange.html I have to assue we are using c=0 because it is convenient for a solution.

OpenStudy (fibonaccichick666):

so anyways, you probably proved e^x in class, so then you change x to a series and e^x into a series then you get your series. At least that is what it looks like to me.

OpenStudy (fibonaccichick666):

no promises, but I hope this helps

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