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Mathematics 7 Online
OpenStudy (dan815):

Division is weird

OpenStudy (dan815):

Addition and subtractions are okay multiplication is a multiple of additions, and multiple of additions can link to exponents but division... it feels out of place But division function pops out of no where, it's more abstract, like a compliment of multiplication and it changes the game by too much. I was thinking about this guy's question, "use the number 8,15,23 to form some number, using the operators : addition,subtraction, multiplication and division." I was thinking, well all the operations are fine except division. It jumps easily, because once division is allowed, even if only one* number is given you are allowed the space of all real numbers! However if division is not allowed, you quickly become constricted to smaller number domains. I dont think you can hit irrationals and fractions, you quickly become restricted to integers. You also cant escape the factor space of the number you are given

OpenStudy (rational):

You can always change an division problem into an multiplication problem \[\dfrac{a}{b}=x\iff a=bx\] ofcourse with some caution to \(b\)

OpenStudy (rational):

that guy's problem is not well defined, there are infinitely many solutions using addition/subtraction alone

OpenStudy (dan815):

right, i did notice that, the numbers he had you can end up with a 1

OpenStudy (dan815):

is there a way to see if a 1 is not posible with some given set of numbers, under addition and subtraction

OpenStudy (dan815):

like u can clearly see if its, 2 evens nothing can be done

OpenStudy (rational):

\[8x+15y = c\] for a given integer \(c\), this equation always has infinitely many solutions

OpenStudy (dan815):

infinitely many integer solutions right

OpenStudy (rational):

yes

OpenStudy (dan815):

is it because the GCD between them is 1?

OpenStudy (rational):

Exactly! \[ax+by=c\] has infinitely many integer solutions iff \(\gcd(a,b)\mid c\)

OpenStudy (dan815):

it kinda feels like vector spaces lol..

OpenStudy (dan815):

like if 2 numbers have different primes.. they form a number basis under linear combination

OpenStudy (rational):

\[32x+24y=26\] has no solution because : \[32x+24y= 8(4x+3y) = 26\] that says 26 is a multiple of 8, which is false. so no solutions.

OpenStudy (rational):

yes we can think of two coprime integers as a basis i guess...

OpenStudy (rational):

that gcd thing is good for testing existence of solutions below link has a simple way to find all integer solutions of a given equation http://math.stackexchange.com/questions/897356/how-to-find-natural-solutions-of-an-equation/897369#897369

OpenStudy (dan815):

heeey u got a gold medal lol :)

OpenStudy (rational):

lol there is a minor mistake in that reply but nobody cared to point it out

OpenStudy (dan815):

ya u i see lol u ssaid (-t,t) at first

OpenStudy (dan815):

but u fixed it anyway :P

OpenStudy (rational):

wow you're alert! i saw that silly mistake today oly when i pulled it up to review

OpenStudy (dan815):

hehe i try to write out each word of the solution in my head so i can keep along

OpenStudy (rational):

but yeah it wont affect the final answer as (-t, t) is as much a null solution as (t, -t)

OpenStudy (dan815):

yeah since t can be negative

OpenStudy (dan815):

ill go see how to work out the diophantine from this knowledge

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