Division is weird
Addition and subtractions are okay multiplication is a multiple of additions, and multiple of additions can link to exponents but division... it feels out of place But division function pops out of no where, it's more abstract, like a compliment of multiplication and it changes the game by too much. I was thinking about this guy's question, "use the number 8,15,23 to form some number, using the operators : addition,subtraction, multiplication and division." I was thinking, well all the operations are fine except division. It jumps easily, because once division is allowed, even if only one* number is given you are allowed the space of all real numbers! However if division is not allowed, you quickly become constricted to smaller number domains. I dont think you can hit irrationals and fractions, you quickly become restricted to integers. You also cant escape the factor space of the number you are given
You can always change an division problem into an multiplication problem \[\dfrac{a}{b}=x\iff a=bx\] ofcourse with some caution to \(b\)
that guy's problem is not well defined, there are infinitely many solutions using addition/subtraction alone
right, i did notice that, the numbers he had you can end up with a 1
is there a way to see if a 1 is not posible with some given set of numbers, under addition and subtraction
like u can clearly see if its, 2 evens nothing can be done
\[8x+15y = c\] for a given integer \(c\), this equation always has infinitely many solutions
infinitely many integer solutions right
yes
is it because the GCD between them is 1?
Exactly! \[ax+by=c\] has infinitely many integer solutions iff \(\gcd(a,b)\mid c\)
it kinda feels like vector spaces lol..
like if 2 numbers have different primes.. they form a number basis under linear combination
\[32x+24y=26\] has no solution because : \[32x+24y= 8(4x+3y) = 26\] that says 26 is a multiple of 8, which is false. so no solutions.
yes we can think of two coprime integers as a basis i guess...
that gcd thing is good for testing existence of solutions below link has a simple way to find all integer solutions of a given equation http://math.stackexchange.com/questions/897356/how-to-find-natural-solutions-of-an-equation/897369#897369
heeey u got a gold medal lol :)
lol there is a minor mistake in that reply but nobody cared to point it out
ya u i see lol u ssaid (-t,t) at first
but u fixed it anyway :P
wow you're alert! i saw that silly mistake today oly when i pulled it up to review
hehe i try to write out each word of the solution in my head so i can keep along
but yeah it wont affect the final answer as (-t, t) is as much a null solution as (t, -t)
yeah since t can be negative
ill go see how to work out the diophantine from this knowledge
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