Question

derivate!!!! HELPPPPP

Answer 1

\[y=2\sqrt{\sqrt{3^{2}+2}+\sqrt{x}}\]

Answer 2

@misty1212

Answer 3

@perl @nincompoop @iambatman

Answer 4

@dan815

Answer 5

\[y=2\sqrt{\sqrt{3^{2}+2}+\sqrt{x}}\]
hi we only need to worry abou that sqrt x after the first chain rule

Answer 6

\[y=2\sqrt{\sqrt{3x^{2}+2}+\sqrt{x}}\]
IS this

Answer 7

I forgot X

Answer 8

\[y=2\sqrt{\sqrt{3^{2}+2}+\sqrt{x}}\]
\[dy/dx=\frac{1}{\sqrt{\sqrt{3^{2}+2}+\sqrt{x}}} *\frac {1}{2\sqrt x}\]

Answer 9

oh the x argh

Answer 10

my os is lagging it wont lemme type u are going ot have to wait

Answer 11

that be a plus inetween there

Answer 12

@aureobs
this would look less hairy if you squared it first and did it implicitly. 2y dy/dx = ......

Answer 13

\[dy/dx=\frac{1}{\sqrt{\sqrt{3x^{2}+2}+\sqrt{x}}} *(\frac {1}{2\sqrt x}+\frac{1}{2\sqrt{3x^{2}+2}}*6x)\]

Answer 14

this lagg is messing up my life