Question

if f(x)=x^(1/2)-3x and g(x)=2x^6-x^(1/2)-x
find g(x) X f(x)

Answer 1

@MelodicSymphony Is there a website i can plug this into?

Answer 2

\(\bf f(x)=x^{\frac{1}{2}}-3x\qquad g(x)=2x^6-x^{\frac{1}{2}}
\\ \quad \\
g(x)\times f(x)\implies (2x^6-x^{\frac{1}{2}})(x^{\frac{1}{2}}-3x)
\)

Answer 3

multiply away

and recall your exponent rules http://www.math-play.com/image-exponents-rules.jpg

Answer 4

would it be -6x^7+2x^(13/2) +3x^2+2x^(3/2)-x? @jdoe0001

Answer 5

or all that but positive 6x^7

Answer 6

one sec

Answer 7

hmmm actaully my fraction additions are a bit off... should a bit more one sec

Answer 8

\(\large {
f(x)=x^{\frac{1}{2}}-3x\qquad g(x)=2x^6-x^{\frac{1}{2}}
\\ \quad \\
g(x)\times f(x)\implies (2x^6-x^{\frac{1}{2}})(x^{\frac{1}{2}}-3x)
\\ \quad \\
2x^6x^{\frac{1}{2}}-2x^6\cdot 3x^1-x^{\frac{1}{2}}x^{\frac{1}{2}}+x^{\frac{1}{2}}\cdot 3x^1
\\ \quad \\
2x^{6+\frac{1}{2}}-6x^{6+1}-x^{\frac{1}{2}+\frac{1}{2}}+3x^{\frac{1}{2}+1}
\\ \quad \\
2x^{\frac{13}{2}}-6x^7-x+3x^{\frac{3}{2}}
}\)


but yours is a bit close

Answer 9

thank you!

Answer 10

yw