Question

f= A(C+D'B)+A' Simplify the boolean expression.
Thanks

Answer 1

F=A(C+D’B) + A’
=A(C(D+D’)+D’B(C+C’)) + A’ [ Since, A+A’=1]
=A(CD+CD’+BCD’+ BC’D’) + A’
=A(CD+CD’(1+B)+BC’D’) + A’
=A(CD+CD’+BC’D’) + A’ [ Since, A+1=1]
=A((1-C’)(1-D’)+CD’+BC’D’) + A’ [ Since, A+A’=1]
=A(1-C’-D’+C’D’ +CD’+BC’D’) + A’
=A(1-C’-D’+C’D’(1+B)+CD’) + A’ [ Since, A+1=1]
=A(1-C’-D’+C’D’+CD’) + A’
=A(1-C’-D’+D’(C+C’)) + A’ [ Since, A+A’=1]
=A(1-C’-D’+D’) + A’
=A(1-C’) + A’
=AC +A’ [ Since, A+A’=1]
=AC+1-A [ Since, A+A’=1]
=1+A(C-1)
=1-AC’ [ Since, A+A’=1]
therefore, Ans: 1-AC'

Answer 2

thank you

Answer 3

No problem. Hope it was correct.