Question

Rationalizing radicals, did I do it right?

Answer 1

\[\frac{ 2 }{ \sqrt[3]{4x^2} }\]
= \[\frac{ 4 }{ 16x }\]

Answer 2

oops I mean it equals \[\frac{ 2\sqrt[3]{1025x} }{ 16x }\]

Answer 3

\[\frac{ 2 }{ \sqrt{4x^2} }\]
first simplify as you can the denominator.
to do this write the denominator as two radicals
\[\sqrt{4}*\sqrt{x^2}=2x\]

Answer 4

Actuallu I did it again and i got 2root3(16x)/4x

Answer 5

oh ok

Answer 6

wrong.

Answer 7

Your question has

\(\sf\Huge \sqrt[3]{4x^2}\) in the denominator not \(\sf\Large\sqrt{4x^2}\)

Answer 8

oh. sorry.

Answer 9

To rationalize the denominator, you need to multiply the number and denominator by the conjugate.
So: