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Mathematics 8 Online
OpenStudy (anonymous):

Can someone help me with trig homework, will fan and medal

OpenStudy (anonymous):

\[(\sin \theta -\cos \theta +1)/\sin \theta+\cos \theta -1) = \sin \theta +1/\cos \theta\]

OpenStudy (anonymous):

I need to show how the left hand side is equal to the right hand side using trig identities

OpenStudy (astrophysics):

Multiply the left side by cos theta

OpenStudy (anonymous):

Are you getting that from the sin+1/cos?

OpenStudy (astrophysics):

No we're working with the left side

OpenStudy (anonymous):

Why would I take out cos?

OpenStudy (astrophysics):

You can how ever after multiply the right side by sintheta+cos theta-1

OpenStudy (astrophysics):

What?

OpenStudy (astrophysics):

Maybe you should show me your work, then we can see what you're thinking

OpenStudy (anonymous):

I'm not allowed to take anything from the right side to help, its just for checking. All I have is the equation written down as it is

OpenStudy (astrophysics):

I'm not doing anything on the right side, all I said was multiply the left side by cos theta

OpenStudy (anonymous):

Where are you getting the cos theta from?

OpenStudy (astrophysics):

You have to deal with trig identities separately, I just assume we need it to simplify the right side.

OpenStudy (astrophysics):

sorry left side*

OpenStudy (astrophysics):

Multiply by cos theta and expand

OpenStudy (anonymous):

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