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Show algebraically that the vertices A (13,3) B (13,5) and C (=2.20) form a right angle triangle.
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1st off , you need to calculate , [AB] , [AC], [BC] we don't where the menu corner is , do you have anyidea what to do next ?
is this to help find the slope of the triangle?
nope not at all
what do you mean by that because I'm already calculating the slope.
we know that , AB² + AC² = BC² if BC is the longest , so A is going to be our square
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ohhhh so I figuerd out the slope for AB and AC now I need figure out BC
AB's slope is \[\frac{ 2 }{ 16 }\]
AC's slope is \[\frac{ -23 }{ -15 }\]
how did you find those ?
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