Question

Simplify (a + 1)!/(a - 2)!

Answer 1

This is Prime, so it cannot be simplified any further.

Answer 2

See how?

Answer 3

There's an answer in the back of the book though...

Answer 4

What are the choices?

Answer 5

I just don't know how to get there
It's a(a+1)(a-1) but I don't understand how to get that

Answer 6

a(a+1)(a-1) is what we are solving then?

Answer 7

No, the question is: Simplify (a+1)!/(a-2)!
And the answer that the back of the book gives is: a(a+1)(a-1)
And I don't understand how to get that

Answer 8

\[(a+1)!=(a+1)\cdot a\cdot (a-1)\cdot (a-2)!\]

Answer 9

I'm still confused...

Answer 10

do you understand what I typed?

Answer 11

Yes, I think so

Answer 12

\[\frac{(a+1)!}{(a-2)!}=\frac{(a+1)\cdot a\cdot (a-1)\cdot (a-2)!}{(a-2)!}\]

Answer 13

\[=\frac{(a+1)\cdot a\cdot (a-1)\cdot \cancel{(a-2)!}}{\cancel{(a-2)!}}\]

\[=(a+1)\cdot a\cdot (a-1)\]

Answer 14

Oh! I got it! Thank you so much :)

Answer 15

np