The area of a polygon of n sides inscribed in a circle of radius r is
\[A=\frac{ nr^2 }{ 2}\sin(\frac{ 2\pi }{ n })\]
If r=12 what is the limit of A as n approaches infinity?
@Michele_Laino
452.39 658.02 37.70 226.19
Thing about this one
we can rewrite your formula as below: \[\Large \frac{{n{r^2}}}{2}\sin \left( {\frac{{2\pi }}{n}} \right) = \frac{{n{r^2}}}{2} \times \left( {\frac{{2\pi }}{n}} \right) \times \frac{{\sin \left( {\frac{{2\pi }}{n}} \right)}}{{\left( {\frac{{2\pi }}{n}} \right)}}\]
now, we have to keep in mind that: \[\mathop {\lim }\limits_{x \to 0} \frac{{\sin x}}{x} = 0\]
so, what do you get?
hold up Im right all this down
Im getting an error
I put in like this http://www.wolframalpha.com/input/?i=nr^2%2F2x%282%283.14%29%2Fn%29xsin%282%283.14%29%2Fn%29%2F%282%283.14%29%2Fn%29
hint: \[\Large \begin{gathered} \frac{{n{r^2}}}{2} \times \left( {\frac{{2\pi }}{n}} \right) \times \frac{{\sin \left( {\frac{{2\pi }}{n}} \right)}}{{\left( {\frac{{2\pi }}{n}} \right)}} = \frac{{n{r^2}2\pi }}{{2n}} \times \frac{{\sin \left( {\frac{{2\pi }}{n}} \right)}}{{\left( {\frac{{2\pi }}{n}} \right)}} \hfill \\ \hfill \\ = \pi {r^2} \times \frac{{\sin \left( {\frac{{2\pi }}{n}} \right)}}{{\left( {\frac{{2\pi }}{n}} \right)}} \hfill \\ \end{gathered} \]
3.14r^2x(sin)(2(3.14)/n)/2(3.14)/n
http://www.wolframalpha.com/input/?i=3.14r^2x%28sin%29%282%283.14%29%2Fn%29%2F2%283.14%29%2Fn
I cant get the text command for that
I keep getting errors every way I put it in
its a error or none of the answers
hint: when n goes to infinity, then: (2 pi/n) goes to zero, so we can write: \[\Large \mathop {\lim }\limits_{x \to 0} \frac{{\sin \left( {\frac{{2\pi }}{n}} \right)}}{{\left( {\frac{{2\pi }}{n}} \right)}} = 1\] sorry, I have made an error, the right formula, is: \[\mathop {\lim }\limits_{x \to 0} \frac{{\sin x}}{x} = 1\]
is it 452.39
that's right!
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