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Mathematics 15 Online
OpenStudy (anonymous):

Help please! On a deadline. Posting below

OpenStudy (anonymous):

Chemists define the acidity or alkalinity of a substance according to the formula pH = –log[H+] where [H+] is the hydrogen ion concentration, measured in moles per liter. Solutions with a pH value of less than 7 are acidic; solutions with a pH value of greater than 7 are basic; solutions with a pH of 7 (such as pure water) are neutral.

OpenStudy (anonymous):

a) Suppose that you test apple juice and find that the hydrogen ion concentration is [H+] = 0.0008. Find the pH value and determine whether the juice is basic or acidic. b) You test some ammonia and determine the hydrogen ion concentration to be [H+]= 1.7 × 10–8. Find the pH value and determine whether the ammonia is basic or acidic.

OpenStudy (anonymous):

@paki @sammixboo

OpenStudy (welshfella):

pH = - log[H+] just plug in value of H+

OpenStudy (welshfella):

and use your calculator to work it out the log is log to base 10

OpenStudy (anonymous):

@Mehek14 @EclipsedStar

OpenStudy (michele_laino):

hint: \[\log 0.0008 = - 3.0969\]

OpenStudy (anonymous):

sorry can't help right now :/

OpenStudy (anonymous):

@Godlovesme

OpenStudy (anonymous):

@Lady.Liv1776

OpenStudy (anonymous):

welll , i can help

OpenStudy (anonymous):

PH = -log[H+], plug in the concentration of the H+

OpenStudy (anonymous):

i dont have one clue how to do this

OpenStudy (anonymous):

just plug in the concentration which is [H+] , -log[H+]

OpenStudy (anonymous):

got it @Ogziii

OpenStudy (anonymous):

how much did you get ? (the PH ) ?

OpenStudy (anonymous):

all i did was write down -log[H+] . How do you get the ph?

OpenStudy (anonymous):

use your calculator , you'll find a log on it , now write down , - log [0.0008] , you'll get a number , thats the PH

OpenStudy (michele_laino):

I got this: pH=-(-3.0969)=3.0969

OpenStudy (anonymous):

How'd you get that? @Michele_Laino Thing is, i dont have a calculator.

OpenStudy (anonymous):

you'll need for a calculator to solve such things ( in the class ) , you could use an online calculator http://web2.0calc.fr/ ,

OpenStudy (michele_laino):

please use Windows calculator

OpenStudy (anonymous):

Got it @Ogziii now what

OpenStudy (anonymous):

now , write , - log [0.0008], you'll get your ph , if it is higher than 7 , it's a base , if it is lower than 7 it's an acid ,

OpenStudy (anonymous):

its an acid

OpenStudy (anonymous):

now what @Ogziii

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (anonymous):

thats all , its an acid is the answer to a ) , now apply the same rule to b , you'll get your answer

OpenStudy (anonymous):

its different from a

OpenStudy (anonymous):

yes , but same rule , -log[H+] , just plug in the new concentration instead of the juice's concentration , you'll get a new PH value , it will determine the answer

OpenStudy (anonymous):

ughh, i dont know why i find this so confusing.

OpenStudy (michele_laino):

for question b. we have: \[\log \left( {1.7 \times {{10}^{ - 8}}} \right) = - 8 + \log \left( {1.7} \right) = - 7.7696\] so: pH=-(-7.7696)=...?

OpenStudy (anonymous):

i guess that we're not supposed to give answers , am i right ? xD

OpenStudy (anonymous):

it'd be 7.7696?

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