Question

rewrite the expression in terms of the given function (1/1+sinx)+(sinx/1-sinx) ; secx

Answer 1

now use the identities
cos^2 x = 1 - sin^2 x

and sec x = 1 / cos x

Answer 2

I got as far as (1/cos^2x)+(sin^x/cos^2x) and the final answer is 2sec^2x-1. I need to know how to get between these steps specifically. Thanks in advanced.

Answer 3

check this

Answer 4

sec^2 x + tan^2x

now sec^2 x = 1 + tan^2 x

tan^2 x = sec^ 2x - 1

so we have

sec^2 x+ sec^2 x - 1
= 2sec^2 x - 1