factor. x^2-12x+32
There is a very good way to factor this kind of mathematical expressions and only applyable for a quadratic mathematical expression (any hgher grade has more complex processes). We will take that expression and make it equal zero: \[x^2 -12x +32 =0\] Why? well, when you make it equal zero, you find the "roots" of the function represented by such mathematical expression and take into a form: (x-a)(x-b) where a and b represent the roots of the function. So, let's take the general formula and solve that for "x": \[x= \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\] \[x= \frac{ 12 \pm \sqrt{12^2 - 4(1)(32)} }{ 2 }\] doing some magical arithmetics and simplifications: \[x= \frac{ 12 \pm \sqrt{16} }{ 2 }\] \[x= \frac{ 12 \pm 4 }{ 2 }\] therefore: \[x_1 = 8\] \[x_2 = 4\] so, the factorized form of the expression would be: \[(x-8)(x-4)\]
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