What is the ratio of x to y?
\(\bf\huge~~~~\color{#ff0000}{W}\color{#ff2000}{e}\color{#ff4000}{l}\color{#ff5f00}{c}\color{#ff7f00}{o}\color{#ffaa00}{m}\color{#ffd400}{e}~\color{#bfff00}{t}\color{#80ff00}{o}~\color{#00ff00}{O}\color{#00ff40}{p}\color{#00ff80}{e}\color{#00ffbf}{n}\color{#00ffff}{S}\color{#00aaff}{t}\color{#0055ff}{u}\color{#0000ff}{d}\color{#2300ff}{y}\color{#4600ff}{!}\color{#6800ff}{!}\color{#8b00ff}{!}\\\bf ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Made~by~TheSmartOne\) Hey there!!! Since you are new here, read this legendary tutorial for new OpenStudiers!! http://goo.gl/5pp1u0 @phfrye12 is there more to your question? Because your question seems incomplete.
is that really the question?
here is an example ratio of a to b is a/b or you can write it as a:b
sorry here it is
act as if you were going to solve for x
do that whole "cross multiplying" thing
once you have x by itself you can divide both sides by y to get x/y
im a little confused on how to do that
what "cross multiply" really means is you are going to multiply both sides by (3x+y) and also multiply both sides by 3
ummmm
A?
I can check your work have you did the "cross multiplication" yet?
do you have a link that i can read over to see if can better understand these problems?
\[\frac{x}{3}=\frac{4}{x}\] pretend like I wanted to attempted to solve for x you can "cross multiply" that is multiply x and 3 on both sides to receive \[x(x)=3(4) \\ x^2=12 \\ x=\pm \sqrt{12}\]
but anyways I'm asking you to just do one step right now the "cross multiplying" part what do you get after doing that?
is it x*x and 3*4?
well for my example you would have yes x*x=3*4 but I was asking about your problem
so
2*3x+y and 3*x
close 2(3x+y)=3x
now distribute on the left hand side
like remember a(b+c) is ab+ac
or a*b+a*c
\[2(3x+y)=3x \\ 2(3x)+2(y)+3x \\ (2 \cdot 3)x+2y=3x\] now multiply the 2 and 3 and get all your x's on one side by subtracting some term on both sides
(5x+y)=3x?
2(3) isn't 5 and you are missing the 2 in front of the y
(6x+y)=3x? sorry typo
well you are still missing the 2 that is suppose to be in front of the y \[6x+2y=3x\] now can you figure out which term you need to subtract on both sides so your x's are seperate from your y's?
you are almost done hang in there
i have no clue i am so bad at these
ok do you that there is a 6x term on the same side as the 2y term
I want x and y on separate sides
I want the 6x term to be with its friend 3x
I want to subtract 6x on both sides so I can make that friendship work out
so what do you have after subtract 6x on both sides of 6x+2y=3x
2y?
well you have 2y on the left hand side what do you have on the right hand side (remembering you are subtracting 6x on both sides)
2y=3x6???
6x+2y=3x -6x -6x 2y=-3x since 3-6=-2 and so (3-6)x=-3x you have 2y=-3x
divide both sides by -3 and divide both sides by y and you have your answer
so is it D?
im sorry im sooo bad at these math problems
@freckles
2y=-3x divide both sides by -3 2y/-3=x now divide both sides by y
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