A store is having a sale on jelly beans and trail mix. For 2 pounds of jelly beans and 5 pounds of trail mix, the total cost is $10 . For 8 pounds of jelly beans and 3 pounds of trail mix, the total cost is $23 . Find the cost for each pound of jelly beans and each pound of trail mix.
So could U show me your steps step by step just as I mentioned before ? Hint : Let abbreviations to be (JM) for Jelly bean and (TM) from trail matrix :D Step by step and don't worry it's very simple as ones before :)
@Omar_Elboredy could you go step by step for me
Let the two unknown unit prices be variables. Let the unit price of jelly beans be b, and let the unit price of trail mix be m.
For 2 pounds of jelly beans and 5 pounds of trail mix, the total cost is $10. If the unit price of jelly beans is b, and you buy 2 pounds, what is the cost of the jelly beans?
$5 @mathstudent55
@Deldrickg Are you there?
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So from the problem statement and abbreviations I told to U : 2JB + 5 TM = 10 & 8JB + 3TM = 23 nw multiply (eq.1) by 4 U will get : 8JB + 20TM = 40 and then substract (eq.2) from the result eq ... U will get then : 17TM = 17 , then TM = 17/17 = 1 $ And finally U substitute back by TM = 1 in any of the equations (eq.1) or (eq.2) ,U will get : JB = 2.5$
2 pounds of jelly beans costs 2b 5 pounds of trail mix costs 5m The total is $10, so you have your first equation: 2b + 5m = 10
You do the same for the second equation, and you get: For 8 pounds of jelly beans and 3 pounds of trail mix, the total cost is $23. 8b + 3m = 23 This is your system of equations:: 2b + 5m = 10 8b + 3m = 23
Multiply the first equation by -4 on both sides and add the equations: -8b - 20m = -40 8b + 3m = 23 ---------------- -17m = -17 Divide both sides by -17 to get m = 1 Now substitute 1 for m in the first equation: 2b + 5m = 10 2b + 5(1) = 10 2b + 5 = 10 2b = 5 b = 2.5 Answer: The jelly beans cost $2.50 per pound, and the trail mix costs $1 per pound.
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