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Mathematics 16 Online
OpenStudy (kj4uts):

Suppose that many large samples are taken from a population and that the sample proportions are normally distributed, with a mean of 0.22 and a standard deviation of 0.029. 99.7% of the sample proportions will fall within which of the following intervals? A. 0.133 to 0.307 B. 0.104 to 0.366 C. 0.162 to 0.278 D. 0.191 to 0.249

OpenStudy (kj4uts):

@perl is this like the other problem you helped me with but in reverse? http://openstudy.com/study#/updates/552f320ae4b0863033976526

OpenStudy (perl):

yes it is similar

OpenStudy (perl):

thanks for linking that

OpenStudy (kj4uts):

no problem thank you for your help all the time. do I still use the same formula?

OpenStudy (perl):

yes we can use that formula (for sample proportions)

OpenStudy (kj4uts):

is n the standard deviation or sample size?

OpenStudy (kj4uts):

because here the standard deviation is 0.029

OpenStudy (perl):

according to the empirical rule, within 3 standard deviations 99.7% of the data falls inside it. so we can use 3 for our z critical score

OpenStudy (kj4uts):

I thought is was .997

OpenStudy (perl):

actually the z score is more like 2.96 but

OpenStudy (kj4uts):

do I multiply the .022 times the .029 I am a little confused on the +-3

OpenStudy (perl):

$$ \Large \rm { \\ p \pm Margin~of~Error \\ p \pm Z_{critical} * (standard~ deviation) \\ 0.22 \pm 3 \times0.029 \\ ( 0.22 - 3 \times0.029, 0.22 + 3 \times0.029) \\ ( .133, .307) } $$

OpenStudy (kj4uts):

srry I lost connection

OpenStudy (kj4uts):

so that would make the answer a. then

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