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Mathematics 14 Online
OpenStudy (ohohaye):

Please Help Me

OpenStudy (ohohaye):

OpenStudy (ohohaye):

Am I right?

OpenStudy (amorfide):

\[(a+b)(a-b)=a^{2}-b^{2}\]

rvc (rvc):

first one right

rvc (rvc):

for the last one use thu property that @amorfide wrote

rvc (rvc):

the*

OpenStudy (anonymous):

the first one is correct. The second one should be -sinx and third one should be (cotx)^2

OpenStudy (ohohaye):

Why would it be cotx though?

OpenStudy (ohohaye):

* (cotx)^2

OpenStudy (amorfide):

part two comes out as \[\frac{ \csc^{2}x-1 }{ sinx }\] \[\sin^{2}x+\cos^{2}x=1\] using this identity if we divide by sin^2x \[1+\cot^{2}x=\csc^{2}x\] \[\frac{ 1+\cot^{2}x-1 }{ sinx }\] we know that cot^2x is cos^2x/sin^2x \[\frac{ \cos^{2}x }{ \sin^{2}x } \times \frac{ 1 }{ sinx }\]

OpenStudy (amorfide):

you can finish that

OpenStudy (ohohaye):

Ok, thanks for the help

OpenStudy (amorfide):

using the identity you can figure out yourself why the last one should be cot^2x

rvc (rvc):

Bravo! All the best @ohohaye

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