a little help? Also, for part 1 you should have the steps for making the angle bisectors and perpendicular bisectors. For part 2 question 2 the intercepted arc is twice the measure of the inscribed angle. This will change your answer. For part 3 question 1 the circles will not be congruent but rather similar. You would need to show that they are similar and provide the similarity ratio. Please go back and make these corrections.
1. Locate the center-point (vertex) of the angle. 2. Place the tip of the compass on the vertex of the angle and draw an arc which cuts each arm of the angle at two different points. Use whatever width of the compass you want to. 3. Place the tip of the compass on one of the points where the first arc cuts an. Draw a second arc small enough to fit between the arms of the angle. 4. Do the same on the other point of the first arc. 5.Draw a line connecting the points of intersection on the arcs. you should now have a bisected angle.?
okay i dont need help withe the constructions just on the part 2 and part 3 things
is this right for part 2 If <ACB is 30° and it is also an inscribed angle, then you can use the Inscribed Angle Theorem to find the arc that it intercepts. The theorem would be <ACB = 1/2 arc. Which is 30° = 1/2 arc. So the inscribed angle is equal to half of the intercepted arc. Therefore, the intercepted arc would be 60°.
@matt101
im having trouble with part 3 question 1
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