Question

Area of the shaded segment=
https://oconomowoc.owschools.com/media/g_geo_2012/8/group103bb.gif

Answer 1

First find the area of sector, which is \[s=\frac{ \theta }{ 360 }*\pi*r^2\] or a=\[s=\frac{ 60 }{ 360 }*\pi*6^2=18.84\]

Answer 2

Next find the area of the triangle inside the sector:
\[A=\frac{ a*b*\sin \theta }{ 2 }\], where a and b are the adjacent sides.
\[A=\frac{ 6*6*\sin60 }{ 2 }=15.59\]

Answer 3

Ultimately, the shaded area or the sector is equal to the difference of the area of sector and the area of triangle. What do you get then @MVen ?

Answer 4

here is what it gives me for answers i think the second one but not exactly sure.
\[6\pi-9\sqrt{3un ^{2}}\]\[12\pi-9\sqrt{3un ^{2}}\]\[9\pi-9\sqrt{3un ^{2}}\]

Answer 5

i know its not the 6pi one

Answer 6

What is u and n?

Answer 7

im guessing angle and radius

Answer 8

Are you not satisfied with my formulas or are those the alternatives?

Answer 9

those are the equations the question is giving me as answers

Answer 10

screen shot of what it is

Answer 11

OOps, my formulas and workout do not match any of those...

Answer 12

haha i know. im not sure what to do for it

Answer 13

i got it right it was the 12 pi one

Answer 14

just guessed

Answer 15

thanks for the help

Answer 16

Right.