A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. What distance has the spaceship covered after 12.0 seconds?

Question

anonymous · Answer

IS IT AN ALIEN SPACESHIP?

welshfella · Answer

use one of the equations of motion for uniform acceleration

welshfella · Answer

u = 58 , v =  153, t = 12

anonymous · Answer

A.6.96 × 102 meters
B.1.27 × 103 meters
C.5.70 × 102 meters
D.1.26 × 102 meters
E.6.28 × 102 meters

welshfella · Answer

d = (u +v) * t
       -----
            2

anonymous · Answer

k figured it out its B

welshfella · Answer

yes that's correct

perl · Answer

$$ 

\Large m {
\ Definition:\
 d= \overline  v \cdot  t 
\~\ For ~ uniform ~ acceleration ~it~ is ~ true~ that
\ \overline  v = \frac{v_i + v_f}{2}
\~\ 	ext{Therefore }\~\
\  d =( \frac{v_i + v_f}{2})\cdot t  

}$$