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Mathematics 16 Online
OpenStudy (anonymous):

Revenue for each car? http://s304.photobucket.com/user/tyronneguillory57/media/giv_zpsdbs83cgn.png.html?o=0

OpenStudy (amistre64):

did we ever determine the problem we had last time?

OpenStudy (anonymous):

Yes. Perl helped me out.

OpenStudy (amistre64):

what was the resolution? just curious

OpenStudy (amistre64):

the sum of xP(x) might help us with this one

OpenStudy (anonymous):

I think 10,769 would be the answer. I multiplied each of them by 52.

OpenStudy (amistre64):

0(1/8) + 1(3/8) + 2(3/8) + 3(1/8) 0 + 3/8 + 6/8 + 3/8 12/8 = 1.5; he expects to sell 1.5 cars a week 52*1.5 = 78 cars a year so 78 cars have to amount to the total losses incured to break even right?

OpenStudy (anonymous):

ok. wouldn't he need to make 560000 dollars for that whole year? So wouldn't 560000 divided by 52= 10769 work?

OpenStudy (amistre64):

560 000 spread over 78 cars is how many per car? 560 000/78 spread over 1 car is how much?

OpenStudy (anonymous):

7179

OpenStudy (amistre64):

then if we expect to sell 78 cars in a year, each car has to bring in at least 7179 in order to cover the total costs for that year

OpenStudy (anonymous):

ok.

OpenStudy (amistre64):

now for extra stuff .... since we expect to sell 1.5 cars a wek, we would need to set a goal of at least making: 7179(1.5) dollars a week

OpenStudy (amistre64):

then we get to your 10770 amount, but its not asking for that in particular is it :)

OpenStudy (anonymous):

So I was just calculating the wrong stuff.

OpenStudy (amistre64):

pretty much, but you were at least in the right direction with your thoughts.

OpenStudy (amistre64):

10770 a week, would need to be divided by the expected number of cars sold to get the expected cash from each car

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