The graph of f ′(x) is continuous and decreasing with an x-intercept at x = 0. Which of the following statements is false? The graph of f has an inflection point at x = 0. The graph of f has a relative maximum at x = 0. The graph of f is always concave down. The graph of the second derivative is always negative.
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somebody has answered this question before i recall check @misty
i mean misty21
was not that you who asked the same quesiton?
it was a different ? but looked similiar
well for me it looks perfectly the same question
it says decreases instead of increases so that changes things
Actually i remember that question said decreases as well hehe
you mean this should be saying increases hehe
@xapproachesinfinity heres the link to the old question. nowhere in that question does it specifically state decreases
http://openstudy.com/users/familyguymath#/updates/552e8df7e4b0cb4951766b74
i'm sure i have seen this same question and misty answered but i don't if that was you at any rate , follow the same reasoning siths did with that question if f' decreases then f''<0 so concaved down f' has and x intercept at x=0 mean f'(0)=0 0 i a critical point so at x=0 we might have an extremum
so its either a or d is what ur saying?
if f' is decreasing and have an x intercept at x=0 then f'>0 before 0 and f'<0 after x=0 so potive to negative means we have and a mix-mum
well read and analyze what i wrote and see what you have to take out
well for inflation we don't have other things about f" that would tell us about it so must be wrong
others just read carefully what i did
i gave you all what you need to answer this just think
@xapproachesinfinity so its just a and d
the only wrong one is a
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