Question

A baseball is thrown upwards from a height of 5 feet with an initial speed of 64 feet per second, and its height h (in feet) from the ground is given by h(t) = 5 + 64t – 16t2 as shown in the graph where t is time in seconds. Using a graphing calculator, at what time does the ball reach its maximum height?

0

1

2

3

Answer 1

Is this 2 or C?

Answer 2

@Michele_Laino

Answer 3

@phi

Answer 4

@sleepyjess

Answer 5

@amistre64

Answer 6

\[ h(t) = – 16t^2 + 64t +5\]
they ask you to use a graphing calculator.
but you can use algebra. match your equation to
\[ y = a x^2 + bx + c\]
the peak occurs at x= -b/(2a)

in your problem, a matches -16 and b matches +64
and the peak is at t= -b/(2a)= -64/(2*-16)

Answer 7

thas 2

Answer 8

yes, t=2 is the top