The sum of the digits of a two digit number is 12 the number formed by interchaning the digits is 54 more than the original number what is the original number? A 39 B48 C57
let's call the number ab where a is the tens digit and b is the ones digit
a+b=12 (the sum of the digits = 12)
and the number itself can be represented as a*10+b (a gets multiplied by 10 because it is the tens digit)
the interchanged number is b*10+a and we're told that the interchanged number is 54 more than the original so we have: a+b=12 10b+a=10a+b+54 that's a system of equations
Wait where did the 54 come from? ._.
the question. do you know what interchanging is?
I'm confused on exactly what it is. /).(\
no shame. basically if we have a number ab, the interchanged number is ba so if we have 36, the interchanged version would be 63
and so that's what I mean when I did the thing with times 10. If our number is 36, it can be written as \((3*10)+6\), aka \(36\) right? the interchanged number, 63, can be written as \((6*10)+3\) aka 63
I really suck at explaining this but this is the site I used to look this up http://www.onlinemathlearning.com/digit-problems.html
I get a bit of what you're saying! :3 Thank you for helping me. :)
so can you solve the system?
It would be 57 right?
well to check it, compare 57 and the interchanged value to start, what is 57 interchanged?
5x10+7?
that's just 57, to interchange it, we flip the digits around
OHHHH! So it would be 75?
yeahhh, and so now compare 57 and 75 is 75-57 = 54?
noo.
which means 57 is not our answer if you're really lazy you could bruteforce your way through and just check each choice like that
It'd be 39! :D
yeah, let me show you how it works if you solve the system tho
okay :)
a+b=12 10b+a=10a+b+54 let's use substitution. we'll start by solving for a: \(a=12-b\) is that much clear?
Mhmm.
we can then plug it into the second equation. \(10b+(12-b)=10(12-b)+b+54\) simplify that and we get \(9b+12=120-10b+b+54\\9b+12=174-9b\\18b=162\\b=\dfrac{162}{18}=9\)
and so that means that our "ones" digit has to be a 9. you can get the tens digit by solving for b and substituting
Ohhh okay.
I can't seem to get a=3, but this calculator agrees with our answer http://www.wolframalpha.com/input/?i=a%2Bb%3D12+%2C10b%2Ba%3D10a%2Bb%2B54
Okay! :D Thank you so much! <3
\(\huge \color{pink}{\heartsuit}\) <3
Join our real-time social learning platform and learn together with your friends!