Question

The function f(x) = 10(5)x represents the growth of a lizard population every year in a remote desert. Crista wants to manipulate the formula to an equivalent form that calculates every half-year, not every year. Which function is correct for Crista's purposes?

Answer 1

pleae help me!!!

Answer 2

please**

Answer 3

i really dont understand how to solve this

Answer 4

as far as I can tell
f(x) means, every "x" value is 1 year
so f(2) is 2 years growth
f(3) 3 years growth and so on

to get half of that, wouldn't that be x/2?

so \(\bf f\left( \frac{2}{2} \right)=f(1year)\qquad f\left( \frac{3}{2} \right)=f(1\frac{1}{2}year)\)

and so on, thus "x" gets spliced in two, giving the two halves

Answer 5

what does that mean?

Answer 6

well.. do you know what the function is doing?

Answer 7

no

Answer 8

those are the answers i am given and it all looks like gibberish

Answer 9

I assume you've covered what a function is already? and what an input and output is?

Answer 10

yes? but I am not clear on it. I am English math is scary to me

Answer 11

on sec

Answer 12

ok

Answer 13

by the time you read this i will have gone ill be back but my parents are bugging me. so i must leave.

Answer 14

oh nvm

Answer 15

\(\large {
\begin{array}{llll}
\textit{lizard population}&f(x)=10(5)^x
\\\hline\\
year&amount
\\\hline\\
1&f(1)\to 10(5)^1\\
2&f(2)\to 10(5)^2\\
3&f(3)\to 10(5)^3\\
4&f(4)\to 10(5)^4\\
5&f(5)\to 10(5)^5\\
...&...
\end{array}
}\)


see how the population is increasing as the years go by?

Answer 16

yes the year is equal to the power

Answer 17

the "x"
accounts for the year amount

so, if you want 6months, or half a year

split the "x" or the year, in half, or x/2

now

if you make f(x) look like \(\bf f\left( \frac{x}{2} \right)\)

what would the expression on the right-hand-side look like then?
\(\bf 10(5)^x\) will look like ?

Answer 18

10/2 ^(5) ^x?

Answer 19

hmm? notice
you're changing the "years"

the 10 is not the years though

Answer 20

\(\large f(year)=10(5)^\textit{year}\qquad f\left( \frac{year}{2} \right)=?\)