Question

Separating the variables in the equation ye^(-x)dy/dx=x gives you the equation:

Answer 1

ye^(-x)dy=xdx
ydy=xe^x dx
ydy=xe^(-x)dx
ydy=xe^(-1/x)dx
None of these. The equation is not separable!

Answer 2

@freckles

Answer 3

-x doesn't equal -1/x

Answer 4

you can use integration by parts to integrate x*exp(-x)

Answer 5

wait

Answer 6

why did you change x to -x?

Answer 7

\[y e^{-x} dy=x dx \\ ye^{-x} e^{x} dy=x e^{x} dx \\ y dy=x e^x dx\]

Answer 8

Those are the possible answers.

Answer 9

oh

Answer 10

lol

Answer 11

Not my work.

Answer 12

haha

Answer 13

separate the variables by multiplying and dividing stuff on both sides

Answer 14

\[y e^{-x} \frac{dy}{dx}=x\]
to separate you can choose to multiply both sides by e^(x) *dx

Answer 15

I think the answer is ydy=xex dx then.

Answer 16

@freckles

Answer 17

sorry e^x

Answer 18

ydy=xe^x dx

Answer 19

y dy=x e^x dx
yep sounds good to me

Answer 20

Thanks!

Answer 21

np

Answer 22

lol I gave you the answer above by accident because I thought you were showing your work

Answer 23

but oh well

Answer 24

Oh, I didn't even notice.

Answer 25

"\[y e^{-x} dy=x dx \\ ye^{-x} e^{x} dy=x e^{x} dx \\ y dy=x e^x dx\]"