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Mathematics 8 Online
OpenStudy (anonymous):

What is the area of the equilateral triangle? Round to the nearest square centimeter.

OpenStudy (anonymous):

OpenStudy (yttrium):

well, let me teach you a derivation that will lead to a certain formula you can apply to all

OpenStudy (michele_laino):

hint: the height of your triangle is: \[8 \times \frac{{\sqrt 3 }}{2} = ...?\]

OpenStudy (yttrium):

|dw:1429341941618:dw| say you have an equilateral triangle with all sides equal to a

OpenStudy (anonymous):

all sides should be 8 right?

OpenStudy (michele_laino):

|dw:1429341836536:dw|

OpenStudy (yttrium):

yes, in your case it is 8

OpenStudy (yttrium):

since all sides are equal, we can also conclude that all angles are equal and that is 180/3 = 60 degrees

OpenStudy (anonymous):

then what do i do

OpenStudy (michele_laino):

the requested area is given by the subsequent formula: \[\Large A = \frac{{base \times height}}{2} = \frac{{8 \times 8 \times \frac{{\sqrt 3 }}{2}}}{2} = ...?\]

OpenStudy (yttrium):

|dw:1429342103469:dw| say we put a height, which is equal to h. by pythagorean identity, sin60 = opposite/hypotenuse = h/a therefore, \[\frac{ \sqrt{3} }{ 2 }a\] we know that area of triangle = \[ = \frac{ 1 }{ 2 }bh\] substituting h, we will get \[A = (\frac{ 1 }{ 2 })\frac{ \sqrt{3} }{ 2 } a = \frac{ \sqrt{3}a }{ 4 }\]

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