How do I use integration by parts to integrate this problem (p^3)(e^(p^2)) from 0 to 1

Question

amistre64 · Answer

rule of thumb, a poly always drives to zero in the end ...

amistre64 · Answer

**derives to zero that is

amistre64 · Answer

@zepdrix  i was curious to see what you were responding with, which is why i didnt make any indepth analysises.  just a commentary.

anonymous · Answer

So I used the poly as u and I got (p^2*e^(p^2))/2 - 3/2 * (integral of p*e^(p^2))) @amistre64

anonymous · Answer

Sorry about the late reply

amistre64 · Answer

the sequence that is generated can be formulated in a table,  the derivatives verses the integrations

sign   du          v
                   2/2 p e^(p^2)
  +    p^2        e^(p^2) / 2
  -      2p          

i think this might be a better view of whats going on

amistre64 · Answer

$$\frac12\int \underbrace{p^2}_{u}~2\underbrace{p~e^{p^2}dp}_{dv}=\frac12\left[p^2~e^{p^2}-\int2

p~e^{p^2}dp \right]$$

anonymous · Answer

gotcha thanx for clearing that up :)