Question

The fertilizer ammonium sulfate, (NH4)2SO4, is prepared by the reaction between ammonia (NH3) and sulfuric acid:
2NH3 + H2SO4 --> (NH4)2SO4
How many kilograms of NH3 are needed to produce 1.40 x 10^5 kg of (NH4)2SO4?

Answer 1

you will need half the amount of nh3 beacuse for every 2 mols of nh3 there is one mole of (NH4)2(SO4) so you just divide it by two.

Answer 2

so you will ned 7*10^4

Answer 3

I'm not following what you are saying.

Answer 4

the equation states that for every 2 moles of nh3 you will get one mole of (nh4)2so4

Answer 5

do you know how i got that?

Answer 6

Not exactly

Answer 7

I went and did what you did getting the 7 x 10^4 but it said it was wrong. That's more where I'm confused. I think I'm seeing where you are getting the numbers. It's from the chemical equation right?

Answer 8

yes and sorry i did it in a hurry earlier see what you have to do is convert 1.4*10^5 kg of (nh4)2s04 to kg of nh3

1.4*10^5(NH4)2SO4

Answer 9

\[\frac{ 1.4*10^5 kg NH4 }{ }*\frac{ 1000g NH4 }{ 1 kg NH4}*\frac{ 1 mole NH4 }{ 132g (NH4)2SO4 }*\frac{ 2 mole NH3 }{ 1 mol (NH4)2SO4 }*\frac{17 g NH3 }{ 1 mole NH3}*\frac{ 1 kg NH3}{ 1000 gNH3 }\]

Answer 10

I got 36060.60606

Answer 11

\[\frac{ 17 g }{ 1 mole nh3}*\frac{ 1 kg NH3 }{ 1000 g}\]

Answer 12

that is the part that didnt fit so divide what you got by 1000 to get kg

Answer 13

36.06

Answer 14

Or would it be .00613

Answer 15

I don't think I'm getting the right answer.

Answer 16

it is the correct answer 3.61*10^4 put it in scientific notation

Answer 17

I see now

Answer 18

Thank you for the help!

Answer 19

Would you be willing to help with another question?

Answer 20

sure