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For the reaction, calculate how many moles of the product form when 0.016mol of O2 completely reacts. Assume that there is more than enough of the other reactant. 2Ca(s)+O2(g)→2CaO(s)
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if you have .016 moles of 02 then .032 mols of product will form
because the equation tells you for every mol of 02 you will get 2 moles of product . so you just multiply the moles by two
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