Question

A point H on a segment with endpoints B (3, -1) and Z (12, 5) partitions the segment in a 5:1 ratio. Find H. How would I go about doing this?

Answer 1

How to do it @vera_ewing

Answer 2

well H is somewhere between B and Z

so using ratios

\[\frac{BH}{HZ} = \frac{5}{1}\]

or \[BH = 5HZ\]

so for x its

\[x_{H} = \frac{5x_{Z} + x_{B}}{ 5 + 1}\]

same for the y values

\[x_{H} = \frac{ 5 \times 12 + 3}{5 + 1}\]

\[x_{H} = \frac{63}{6}\]

here is a site that explains it quite well

http://www.teacherschoice.com.au/Maths_Library/Analytical%20Geometry/AnalGeom_3.htm

Answer 3

If I'm given an equation or if someone can help me through the problem I'm willing to work on it and understand it. I'm not looking for the answer to the question. I'm looking to work on it.

Answer 4

5:1 ratio on a segment
means the segment is split in 6 pieces

5 on one side
1 on the other

so one side is 5 times, the length of the other
5 to 1, 5:1 ratio 5/1

notice campbell_st 's line above

Answer 5

okay! so do i need to find the distance of the line?

Answer 6

and then figure out 1/6 of that answer and place H closer to Z?

Answer 7

so hmmm one sec

Answer 8

no you don't need to find the distance... you can actually graph the line...



divide the dotted sides in the ratio 5:1 to find the point

Answer 9

(7,4)?
12-5 and 5-1?

Answer 10

use the unitary method

5:1 means 6 parts in the ratio

so 9/6 = 1.5

so 5 parts is 5x1.5 = 7.5

so 7.5 units horizontally from 3

vertically 6/6 = 1

5x 1 = 5 so 5 parts vertically from - 1